3D Euclidean Distances
Segment AD:0.00
Segment DB:0.00
Total Side AB:0.00
Segment AE:0.00
Segment EC:0.00
Total Side AC:0.00
Segment DE:0.00
Base BC:0.00
Proportionality Verification
PRIMARY THEOREM RATIO
ADDB
= 0.667
=
AEEC
= 0.667
Equal Ratios Verified!
COROLLARY (PART / WHOLE)
AD / AB:
0.400
AE / AC:
0.400
DE / BC:
0.400
NCERT Proof Summary: $\frac{\text{ar}(\Delta ADE)}{\text{ar}(\Delta BDE)} = \frac{AD}{DB}$ and $\frac{\text{ar}(\Delta ADE)}{\text{ar}(\Delta CDE)} = \frac{AE}{EC}$. Since $\Delta BDE$ and $\Delta CDE$ lie on the same base $DE$ and between the same parallels $DE \parallel BC$, $\text{ar}(\Delta BDE) = \text{ar}(\Delta CDE)$.